3y^2-5y+2=3

Solution for 3y^2-5y+2=3 equation:

3y^2-5y+2=3

We move all terms to the left:

3y^2-5y+2-(3)=0

We add all the numbers together, and all the variables

3y^2-5y-1=0

a = 3; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·3·(-1)
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{37}}{2*3}=\frac{5-\sqrt{37}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{37}}{2*3}=\frac{5+\sqrt{37}}{6}
$